pH=-log10[H+]
For example, if a solution has 1.0*107 M H+, then the pH=-log10[1.0*107]=7.
At the same time, we also have pOH.
pOH= -log10[OH-]
For example, if a solution has 1.0*108 M OH-, then the pOH=-log10[1.0*108]=8
However, generally, people only use pH instead of using both pH and pOH. The relationship between pH and pOH: pH+pOH=14 (at room temperature 25。C)
That is because the product of concentration of H+ and OH- always equal to 1.0*10-14 M at 25。C.
[H+][OH-]=1.0*10-14 M
So, we can know the pOH just by using 14 subtract the pH, and do not have to measure the concentration of OH- in the solution.
Image from: Acids-and-Alkalis-The-pH-Scale.png
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